Question

find 4 different solution of 4x+y=a​

Answer 1

Step-by-step explanation:

(i)4x+y=9

If x=0 then

x×0+y=9

⇒y=9

(0,9)

(ii)4x+y=9

If y=0 then

4x+0=9

⇒4x=9

⇒x=

4

9

(

4

9

,0)

(iii)4x+y=9

If x=1 then

4×1+y=9

⇒4+y=9

⇒y=9−4=5

(1,5)

(iv)4x+y=9

If y=1 then

4x+1=9

⇒4x=9−1=8

⇒x=2

(2,1)

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