Question

find 4 different solutions of x+3y=5​

Answer 1

Answer:

IF X = 0,

3Y = 5 => Y = 5/3

IF X = 1,

1 + 3Y = 5 => 3Y = 4 => Y = 4/3

IF X = 2,

2 + 3Y = 5 => 3Y = 3 => Y = 1

IF X = 3,

3 + 3Y = 5 => 3Y = 2 => Y = 2/3

SO, SOLUTIONS ARE,

(0, 5/3), (1, 4/3), (2, 1), (3, 2/3)

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Answer 2

Answer:

1) let x=5 and y=0

5+3(0)=5

2) let x=-1 and y=2

-1+3(2)=5

3) let x=2 and y=1

2+3(1)=5

4) let x= -4 and y=3

-4+3(3)=5