Question

find 4 numbers whose sum is 45,if the first number is 8 and the first number+ 2 = second number - 2 = third number × 2 = fourth ÷ 2 ​

Answer 1

given first number is 8

let the second number be x

from above

8+2=x-2

x=8+2+2=12

let the third be y

yx2=12-2

y=10/2=5

let fourth number be a

z÷2=5×2

z=20

so the 4 numbers are 20 ,5, 12 and 8