Question

Find 4 possible factors of 64x2y2z​

Answer 1

Step-by-step explanation:

Start at 1: 1×20=20, so put 1 at the start, and put its "partner" 20 at the other end:

1 20

Then try 2. 2×10=20 works, so put in 2 and 10:

1 2 10 20

Then try 3. 3 doesn't work (3×6=18 is too low, 3×7=21 is too high).

Then try 4. 4×5=20 works, so put them in:

1 2 4 5 10 20

There is no whole number between 4 and 5 so you are done! (Don't forget the negative ones).

1 2 4 5 10 20

-1 -2 -4 -5 -10 -20