Find 4 solutions for each of the following questions:
a) 2(x-3) -3 (y-1) =0
b)2(x-1) +3y =4
c) (x-4) -y+4=0
d) 2x+3 (y-2)=1
Haroon7:
you should do like this,if x=1,then y?,then if x=2,y=?? like that
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a) 2(x-3) -3 (y-1) =0
(1) Put x=0
=> 2(0-3)-3(y-1)=0
=> -6-3y+3=0
= -3y= 3=> y= -1
(2 )Put x=1
=> 2(1-3)-3(y-1)=0
=> -4-3y+3=0
=> -3y=1=> y= -1/3
(3) Put x=-1
=> 2(-1-3)-3(y-1)=0
=> -8-3y+3=0=> -3y= 5=> y=-5/3
(4)Put x=2
=> 2(2-3)-3(y-1)=0
=> -2-3y+3=0=> y=1/3
b)2(x-1) +3y =4
(1) put x= 0
=> 2(0-1)+3y=0
=> -2+3y=0=> y=2/3
(2) put x= 1
=> 2(1-1)+3y=0
=> 0+3y=0=> y=0
(3) put x= -1
=> 2(-1-1)+3y=0
=> -4+3y=0=> y=4/3
(4) put x= 2
=> 2(2-1)+3y=0
=> 2+3y=0=> y=-2/3
c) (x-4) -y+4=0
(1) Put x=0
=> (0-4)-y+4=0
=> y=0
(2) Put x=1
=> (1-4)-y+4=0
=> -3-y+4=0
=> y=1
(3) Put x=-1
=> (-1-4)-y+4=0
=> -5-y+4=0
=> y=-1
(4) Put x=2
=> (2-4)-y+4=0
=> -2-y+4=0
=> y=2
d) 2x+3 (y-2)=1
(1) Put x=0
=> 2(0)+3(y-2)=1
=> 0+3y-6=1
=> y=7/3
(2) Put x=-1
=> 2(-1)+3(y-2)=1
=> -2+3y-6=1
=> y=9/3=3
(3) Put x=1
=> 2(1)+3(y-2)=1
=> 2+3y-6=1
=> y=5/3
(4)Put x=2
=> 2(2)+3(y-2)=1
=> 4+3y-6=1
=> y=3/3=1
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