Math, asked by Haroon7, 1 year ago

Find 4 solutions for each of the following questions:
a) 2(x-3) -3 (y-1) =0
b)2(x-1) +3y =4
c) (x-4) -y+4=0
d) 2x+3 (y-2)=1


Haroon7: you should do like this,if x=1,then y?,then if x=2,y=?? like that

Answers

Answered by khanujarashmit
3
a) 2(x-3) -3 (y-1) =0 (1) Put x=0 => 2(0-3)-3(y-1)=0 => -6-3y+3=0 = -3y= 3=> y= -1 (2 )Put x=1 => 2(1-3)-3(y-1)=0 => -4-3y+3=0 => -3y=1=> y= -1/3 (3) Put x=-1 => 2(-1-3)-3(y-1)=0 => -8-3y+3=0=> -3y= 5=> y=-5/3 (4)Put x=2 => 2(2-3)-3(y-1)=0 => -2-3y+3=0=> y=1/3 b)2(x-1) +3y =4 (1) put x= 0 => 2(0-1)+3y=0 => -2+3y=0=> y=2/3 (2) put x= 1 => 2(1-1)+3y=0 => 0+3y=0=> y=0 (3) put x= -1 => 2(-1-1)+3y=0 => -4+3y=0=> y=4/3 (4) put x= 2 => 2(2-1)+3y=0 => 2+3y=0=> y=-2/3 c) (x-4) -y+4=0 (1) Put x=0 => (0-4)-y+4=0 => y=0 (2) Put x=1 => (1-4)-y+4=0 => -3-y+4=0 => y=1 (3) Put x=-1 => (-1-4)-y+4=0 => -5-y+4=0 => y=-1 (4) Put x=2 => (2-4)-y+4=0 => -2-y+4=0 => y=2 d) 2x+3 (y-2)=1 (1) Put x=0 => 2(0)+3(y-2)=1 => 0+3y-6=1 => y=7/3 (2) Put x=-1 => 2(-1)+3(y-2)=1 => -2+3y-6=1 => y=9/3=3 (3) Put x=1 => 2(1)+3(y-2)=1 => 2+3y-6=1 => y=5/3 (4)Put x=2 => 2(2)+3(y-2)=1 => 4+3y-6=1 => y=3/3=1

kvnmurty: good
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