find 4 solutions of 2x-y-5
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The given equation is 2x+y=7 ... (1)
Putting x=0 in (1), we get,
2×0+y=7
⇒x=
2
7
∴(
2
7
,0) is a solution of (1).
Further, putting y=1 in (1), we get
2x+1=7
⇒2x=7−1
⇒2x=6
⇒x=3
∴(3,1) is a solution of (1).
Hence, (0,7);(
2
7
,0) and (3,1) are three solutions of the given equation.
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