Question

find 41st term of AP whose 12th term is 39 and 19th term is 88​

Answer 1

Answer:

Step-by-step explanation:

Let 12 term - a+11d=39 (1)

---19th - a+18d=88 (2)

Solving eqn 1 &2

We get a= -38

d = 7

So 41st term - a+40d = -38+ (40×7) = 242