find 4cd ( c2 + d2) if c+d =11 , c-d =1
Answers
Answered by
46
Heya!!
---------------------------
c+d = 11
c-d = 1
Add both eq
=) c+d + c-d = 11+1
=) 2c = 12
=) c= 12/2 = 6
Hence d = 11-6
= 5.
= 4cd(c^2 + d^2)
= 4*6*5 ( 5^2 + 6^2)
= 120(25+36)
= 120* 61
= 7320
Hope it helps uh :)
---------------------------
c+d = 11
c-d = 1
Add both eq
=) c+d + c-d = 11+1
=) 2c = 12
=) c= 12/2 = 6
Hence d = 11-6
= 5.
= 4cd(c^2 + d^2)
= 4*6*5 ( 5^2 + 6^2)
= 120(25+36)
= 120* 61
= 7320
Hope it helps uh :)
Answered by
10
Answer:
Heya!!
Given :-
- c+d =11
- c-d =1
( FROM C+D=11 & C-D=1)
- c = 6.
- d=5
To Find :-
- 4cd ( c2 + d2)
Solution :-
= 4×6×5(6^2+5^2)
= 120×61
= 7320
Hence the the answer is 7320
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