Question

find (4p-3q) power 2 using suitable identity

Answer 1

Answer:

(4p-3q)²

using identity (a-b)² = a²+b²- 2ab

(4p)²+(3q)²- 2×4p×3q

16p²+9q²-24pq

Answer 2

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Solution:

$\: \: \: \: \sf \dag \: {(4p - 3q)}^{2}$

Formula to be used:

$\Huge{\sf{\underline{\fbox{\red{{a - b}^{2}={a}^{2}+{b}^{2}-2 •a•b}}}}}$

Now, put the values after knowing the formula

$\: \: \: \: \: \: : \sf \implies \: {(4p)}^{2} + {(3q)}^{2} - 2.4p.3q \\ \\ \\ \: \: \: \: \: \: \: : \sf \implies \: 16 {p}^{2} + 9 {q}^{2} - 24pq$

Hence, we find the value of (4p - 3q) ^2.

$\Huge{\sf{\red{\underline{know\:more\:info࿐}}}}$

• (a + b) ^2 = (a) ^2 + (b)^2 +2ab
• (a^2 +b^2)=(a + b) ^2 -2ab
• (a^2 - b^2)=(a +b ) (a-b)

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