Question

find 4y^3-8y^2-9y+18​

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

(((4 • (y3)) - 23y2) + 9y) - 18

STEP

2

:

Equation at the end of step

2

:

((22y3 - 23y2) + 9y) - 18

STEP

3

:

Checking for a perfect cube

3.1 4y3-8y2+9y-18 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4y3-8y2+9y-18

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 9y-18

Group 2: 4y3-8y2

Pull out from each group separately :

Group 1: (y-2) • (9)

Group 2: (y-2) • (4y2)

-------------------

Add up the two groups :

(y-2) • (4y2+9)

Which is the desired factorization