FIND
5+COSEC^2 (90*-THETA) -TAN^2 THETA
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Here is your answer :-
In simple way , your question is
5+cosec²(90°-A) - tan²A ( assuming theta as A )
5 + sec²A - tan²A [ cosec(90°-A) = secA ]
5 + 1 = 6 [ sec²A - tan²A = 1]
Your answer is 6 .
if u like my answer then pls mark as Brainiliest
In simple way , your question is
5+cosec²(90°-A) - tan²A ( assuming theta as A )
5 + sec²A - tan²A [ cosec(90°-A) = secA ]
5 + 1 = 6 [ sec²A - tan²A = 1]
Your answer is 6 .
if u like my answer then pls mark as Brainiliest
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