Math, asked by mnmoney4u, 13 days ago

find 5 irrational number between 3/6 and 4/6​

Answers

Answered by KEVIN2010
0

Answer:

Let x = 3/4 ; y = 5/6

y > x ; n = 5

d = y - x/n + 1

= (5/6 - 3/4)/5 + 1

= (10 - 9/12)/6

= (1/12)/6

= 1/12 ÷ 6

= 1/12 × 1/6

= 1/72

1st rational number = x + d

= 3/4 + 1/72

= 54 + 1/72

= 55/72

2nd rational number = x + 2d

= 3/4 + 2 × 1/72

= 3/4 + 2/72

= 54 + 2/72

= 56/72

3rd rational number = x + 3d

= 3/4 + 3 × 1/72

= 3/4 + 3/72

= 54 + 3/72

= 57/72

4th rational number = x + 4d

= 3/4 + 4 × 1/72

= 3/4 + 4/72

= 54 + 4/72

= 58/72

5th rational number = x + 5d

= 3/4 + 5 × 1/72

= 3/4 + 5/72

= 54 + 5/72

= 59/72

Step-by-step explanation:

Answered by rkcomp31
1

Answer:

Step-by-step explanation:

3/6=1/2=0.5

and 4/6=2/3=0.66666666....

Thus the irrational numbers between 3/6 and 4/6 can be:

0.5005000500000-------------

0.520520052000-------------

0.5303003000-------------

0.6101001000-------------

0.6303003000-------------

Similar questions