Math, asked by agovil05, 10 months ago


Find 5 irrational numbers between 3/7 and 6/11​

Answers

Answered by saanvi549
3

Answer:

irrational number between a and b is√ab

if ' a ' be 3/7 and ' b ' be 6/11

then irrational number between them=√3/7×6/11

=√9/77=√9/√77 =

3/√77

now let 'a' be 3/7 and 'b' be 3/√77 then,

irrational number between them= √3/7×3/√77=√9/7√77=

√9/7√77=3/7√77

thus the irrational numbers between 3/7 nd 6/11 is "3/√77" nd "3/7√77"

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Answered by adharshk31
2

Answer:

Irrational number between a and b is√ab

if a=3/7 and b=6/11

then irrational number between them are√3/7×6/11

=√18/77

one irrational number is√18/77

now take a=3/8 and b =√18/77 irrational number is√(3/7)×(√18/77)

=√(3√18/7√77

=18√3/77√7

Step-by-step explanation:

Another method

3/7=0.428...

6/11=0.545...

irrational number between 6/11 and 3/11 are 0.4727392....

0.5378836...

you can insert any non terminating and non repeating numbers between 0.428...and0.545...

hope this is helpful

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