Question

find 5 nubers in the ap whose sum is 25 and the sum of whose squares is 135

Answer 1

Answer:

Step-by-step explanation:

Five numbers in a. p. whose sum is 25 and the sum of whose squares is 135:

5a + 10d = 25

a^2 + (a + d)^2 + (a + 2d)^2 + (a + 3d)^2 + (a + 4d)^2 = 135

Solutions:

a = 3, d = 1

3, 4, 5, 6, and 7

a = 7, d = -1

7, 6, 5, 4, and 3