Question

find √5 on no. line​

Answer 1

Answer:

Step-by-step explanation:

Step 1: Draw a number line. Mark O as the zero on the number line.

Step 2: Mark a point A as -5 on the number line.

Step 3: Mark a point C as 1 on the number line.

Step 4: Mark a point B as the mid-point of AC.

Step 5: With point B as the centre and radius as AB draw a semicircle.

Step 6: From O draw a perpendicular line to the number line that intersects the previous drawn semi-circle at D. Here OD = square root of 5.

Step 7: With O as centre and radius as OD, draw an arc that intersects the number line at point E. Here E is the point square root of 5 on the number line.

Answer 2

To Represent $\sqrt{5}$ on number line.

• Draw a Number line and mark a Point 0, representing Zero,on it.

• Suppose Point A represent 1 as shown in Figure . Then OA= 1.

• Now, Draw a right triangle OCB such that AB=1,OB= 2

By pythogoras theorem.

$\implies\rm{(OB)^2=(OA)^2+(AB)^2}$

$\implies\rm{(2)^2+1^2}$

$\implies\rm{4+1=5}$

$\implies\rm{OC=\sqrt{5}}$

Taking O as the center and OB √5 as a radius draw an arc cutting real line at C. Clearly OB= OC=√5.