Find 5 solutions of y=1 and draw a graph..
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For equation x–y+1=0 or x=y−1, we have following points which lie on the line
Plug y=0,1 we get
x=0−1=−1
x=1−1=0
Therefore, the required points are (−1,0),(0,1).
For equation 3x+2y–12=0 or y=
2
12−3x
, we have following points which lie on the line
Plug x=0,4 we get
y=
2
12−0
=6
y=
2
12−12
=0
Therefore, the required points are (0,6),(4,0).
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