Question

Find 5cm of first 50 natural numbers

(a) 1200 (b) 1250 (c)1275 (d) 1300​

Answer 1

Answer:

Option B

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Sn = (n/2)*[2a +(n-1)d].......

(n) = no. of terms = (50)

(a) = first term = (1)

(d) = common difference = (1)

Sn = (50/2)*[(2*1) + (50-1)*1]

Sn = 25*[2+ (49*1)]

Sn = 25*[2+49]

Sn = 25*51

Sn = 1275 ANSWER

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