Question

find 5sinA-2cosA/6cosA+sinA if 2cotA=3 plss ansr I will mark it as a brainliest​

Answer 1

Answer:

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Answer 2

Answer:

ans: cotA=3/2 =B/P

H=√B^2 +P^2

H=√3^2 +2^2

H=√13

sinA=2/√13 ,cosA=3/√13

ATQ

5sinA-2cosA/6cosA+sinA

=[5(2/√13) - 2(3/√13)] / [6(2/√13) +(2/√13)]

=[10/√13 -6/√13] /[12/√13 +2/√13]

=[4/√13] / [14/√13]. (√13 get cancelled)

=[4/14]

ans =[2/7]