Find 5th term of an A.P whose n term in 3n-5
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The nth term of an AP is given as 3n-5, so the first term is 3*1–5 = -2.
The second term is 3*2–5 = 1.
The common difference = 1-(-2) = 3.
Fifth term = 7+3 = 10
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Answer:
An=3n-5
A5=3(5)-5
A5=15-5
A5=10
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