find 5th term of an AP whose n th term is 3n-5
Answers
Answered by
88
We have to find fifth term, hence n=5
Substituting value of n in given equation we get,
T(n) =3n-5
T(5)=3(5)-5
=15-5
=10
Hence 5th term of given AP is 10
Substituting value of n in given equation we get,
T(n) =3n-5
T(5)=3(5)-5
=15-5
=10
Hence 5th term of given AP is 10
Answered by
31
Answer:
Explanation:
Given
=$ t_{5}$
=$3\times 5 -5$
=$ 15-5$
= $10$
Therefore,
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