Question

find 6+3i/2-i in the form a+ib​

Answer 1

answer is 27/5 +6i/5..........

Answer 2

Answer:

6+3i/2-i

=(6+3i)(2+i)/(2-i)(2+i)

= 12+6i+6i-3/2²-i²

=9+12i/4+1

= 9/5+i12/5 (i²=-1)

here, a=9/5, b=12/5

hope it helps!!