Question

find 6 angles for which sin theta=-√3/2​

Answer 1

Step-by-step explanation:

sin θ = -√3/2 = - sin π/3 = sin 4πr/3

sinθ = sin 4πr/3

θ = nπ + (-1)^n (4π/3)

Now we will put the value of n here

n = 1,2,3,4,5,6

means we can get the 6 different values when trying to find n.