find 6 digit that number when we add 45 then the sum is completely divide by 159
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Answer:
First, we find the LCM of 48 and 108 = 432
the smallest six digit number = 100000
100000÷432 =
quotient = 231
remainder = 208
the required number = 100000 - remainder + LCM = 100000 - 208 + 432 = 100224.
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