Question

Find 6 rational numbers between -5/3
and -8/7​

Answer 1

Answer:

therefore, six rational numbers b/ w 55/77 and 99/77 are: 56/77, 59/77, 75/77, 81/77, 89/77, 96/77

Answer 2

Answer:

Six rational numbers between -5/3

and -8/7 are $( - \frac{34}{21} ),( - \frac{33}{21}),( - \frac{32}{21} ),( - \frac{31}{21} ),( - \frac{30}{21} ),( - \frac{29}{21} )$

Step-by-step explanation:

Here given two fractions are $( - \frac{5}{3} )$ and $( - \frac{8}{7} )$

We want to find six rational number between given two rational numbers.

But question is what is rational number?

Any number that can be written as a fraction of two integers is called a rational number.

Here first we need to make denominator same of both fraction.

First we are taking the fraction $( - \frac{5}{3} )$

We are multiplying denominator and numerator by 7 and get $( - \frac{35}{21} )$

Then we are taking the fraction $( - \frac{8}{7} )$

We are multiplying denominator and numerator by 3,

$( - \frac{8 \times 3}{7 \times 3} ) = ( - \frac{24}{21} )$

Now, six rational numbers between $( - \frac{35}{21} )$ and $( - \frac{24}{21} )$ are

$( - \frac{34}{21} ),( - \frac{33}{21}),( - \frac{32}{21} ),( - \frac{31}{21} ),( - \frac{30}{21} ),( - \frac{29}{21} )$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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