Question

Find

(61 + 62 + 63 + ……… +110) = ?​

Answer 1

This is an A.P.

Given that : a = 61 , d = 1, n = 50 l = 110

As we know that :

$s_{n} = \frac{n}{2} (a + l) \\ \\ = > s_{n} = \frac{50}{2} (61 + 110) \\ \\ = > s_{n} = 25 \times 171 \\ \\ = > s_{n} = 4275$

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