Math, asked by shoshanamurugesan, 3 months ago

Find 68÷ 12/5

Add: 〖4x〗^2-8xy+6y^2 and 〖-12x〗^2-4xy+〖3y〗^2.

Answers

Answered by zoyham6
1

Answer:

find=28.3

add:=−32x2−8y2−30xy

Step-by-step explanation:

find :68x5/12

=28.3

add:A=4x2+y power2−6xy

B=3y power2+12x2+8xy

C=6x2+8ypower2+6xy

A−3B=(4x2+y2−6xy)−3(3y power2+12x2+8xy)

=(4x2+y power2−6xy)−(36x2+9ypower2+24xy)

=−32x2−8y2−30xy

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