find 6sin23+sec79+3tan48/cosec11+3cot42+6cos67
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[ 6 sin23 + sec79 + 3 tan48 ] / [cosec 11 + 3 cot 42 + 6 cos 67 ]
sin 23 = cos(90-23) = cos 67
Sec79 = cosec(90- 79) = cosec 11
tan 48 = cot (90 - 48) = cot 42
so answer is = 1 as the numerator and denominator are equal.
Read more on Brainly.in - https://brainly.in/question/661988#readmore
sin 23 = cos(90-23) = cos 67
Sec79 = cosec(90- 79) = cosec 11
tan 48 = cot (90 - 48) = cot 42
so answer is = 1 as the numerator and denominator are equal.
Read more on Brainly.in - https://brainly.in/question/661988#readmore
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