Math, asked by itzjiajk, 2 months ago

Find
8/6x+12 = -11/7x-10

Answers

Answered by pihu4976
1

Answer:

Hope it helps you!!!!!!

Attachments:
Answered by MasterDhruva
5

How to do :-

Here, we are given with an equation in which there are constants and variables. It's also known as a simple equation. In this we are asked to find the value of a variable 'x'. So, here we are going to use other concepts which are very helpful in solving these type of problems. The first step in this is to be remembered which will be applied to all the type of simple equations. That is, we should always shift the constants in one side and the variables on the other side. So, let's solve!!

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Solution :-

{\tt \leadsto \dfrac{8}{6}x + 12 = - \dfrac{1}{7}x - 10}

Shift all the constants on RHS and all the variable sin LHS.

{\tt \leadsto \dfrac{8}{6}x + \dfrac{11}{7}x =  - 10 - 12}

Now, make the denominators same in LHS by taking the LCM and also silver the numericals in RHS.

{\tt \leadsto \dfrac{56x + 66x}{42} =  - 22}

Now, add the numbers in numerator.

{\tt \leadsto \dfrac{122x}{42} =  - 22}

Shift the denominator from LHS to RHS, changing it's sign

{\tt \leadsto 122x =  - 22 \times 42}

Multiply the numbers in RHS.

{\tt \leadsto 122x =  - 924}

Shift the number 122 from LHS to RHS, changing it's sign.

{\tt \leadsto x = \dfrac{( - 924)}{122} }

Write the fraction in lowest form by cancellation method to get the final answer.

{\tt \leadsto x = \cancel \dfrac{( - 924)}{122} }

Now, write the value of that.

{\tt \leadsto \pink{\underline{\boxed{\tt x = \dfrac{( - 462)}{61}}}}}

\Huge\therefore The value of 'x' is \tt \dfrac{(-462)}{61}

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