Question

find 8(x³-1/x³) if 2x-2/x = 3​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given:-

2x-2/x = 3

To find:-

find 8(x³-1/x³) if 2x-2/x = 3

Solution:-

Given that :2x-2/x=3

=>2(x-1/x)=3

=>(x-1/x)=3/2------(1)

On cubing both sides then

=>[(x-(1/x))]³=(3/2)³

=>[x-(1/x)]³=27/8

=>[(x³-(1/x)³-3(x)(1/x)(x-1/x)]=27/8

=>[x³-1/x³-3(3/2)]=27/8 (from(1))

=>x³-(1/x³)-(9/2)=27/8

=>x³-(1/x³)=(27/8)+(9/2)

=>x³-(1/x³)=(27+36)/8

=>x³-(1/x³)=63/8

=>8[x³-(1/x³)]=63

Answer:-

The value of 8[x³-(1/x³)]=63

Used formula:-

• (a-b)³=a³-3a²b+3ab²-b³
• (a-b)³=a³-b³-3ab(a-b)