find 8x^3 - 1/8x^3, when 2x - 1/2x = p
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Ans:- Given
a. 2x - 1/2x = p
To find,
8x³ - 1/8x³
Solution:-
=> (2x - 1/2x)³ = (p)³
=> 8x³ - 1/8x³ - 3 × 2x × 1/2x(2x - 1/2x) = p³
=> 8x³ - 1/8x³ - 3 × p = p³
=> 8x³ - 1/8x³ = p³ + 3p
=> 8x³ - 1/8x³ = p(p² + 3)
here is your answer
hope it will help you
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