Math, asked by Anonymous, 7 months ago

find 8x cube+27y cube if 2x+3y=8 and xy=2

Answers

Answered by shrutiwaghmode100

1

Answer:

Given,

2x+3y=8

XY=2

Since,

(A+B)³=a³+b³+3ab(a+B)

:.(2x+3y)³=(2x)³+(2y)³+3(2x)(3y)(2x+3y)

Putting value

8³=8x³+27y³18(2)(8)

512=8x³+27y³+288

512-288=8x³+27y³

224=8x³+27y³

(ÆÑẞWĒR)

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