Find 8x³+27y³if 2x+3y=14 and xy =8
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Given : 2x + 3y = 14 and xy = 8
To find the value of 8x³+27y³
Identity: a^{3}+b^3} =(a+b)^{3} - 3ab(a+b)
Now, we shall calculate 8x³+
27y³
8x³+27y³ = (2x + 3y)³ - 3(2x) (3y) (2x + 3y)
or, 8x³ + 27y³ = (2x + 3y)³ – -
18xy(2x + 3y)
Now, substituting the given values in equation (i), we have
8x³+27y³ = (14)³ – 18(8)(14) -
or, 2744 - 2016 =
or, = 728
Hence, the required value of 8x³+27y³ will be 728.
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