Math, asked by kumarsharmamayank123, 1 month ago

Find 8x³+27y³if 2x+3y=14 and xy =8

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Answers

Answered by Anonymous
3

Given : 2x + 3y = 14 and xy = 8

To find the value of 8x³+27y³

Identity: a^{3}+b^3} =(a+b)^{3} - 3ab(a+b)

Now, we shall calculate 8x³+

27y³

8x³+27y³ = (2x + 3y)³ - 3(2x) (3y) (2x + 3y)

or, 8x³ + 27y³ = (2x + 3y)³ – -

18xy(2x + 3y)

Now, substituting the given values in equation (i), we have

8x³+27y³ = (14)³ – 18(8)(14) -

or, 2744 - 2016 =

or, = 728

Hence, the required value of 8x³+27y³ will be 728.

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