Question

Find 9% of12% of 1200.​

Answer 1

Answer:

=9×12×1200

=129600

Step-by-step explanation:

refer to the attachment

Answer 2

\blue{\bold{\underline{\underline{Answer:}}}}

Answer:

\green{\tt{\therefore{Amount=21424.5\:rupees}}}∴Amount=21424.5rupees

\green{\tt{\therefore{Compound\:Interest=1424.5\:rupees}}}∴CompoundInterest=1424.5rupees

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

Step−by−stepexplanation:

\begin{gathered}\green{\underline \bold{Given :}} \\ \tt:\implies Principal(p) = 20000 \: rupees \\ \\ \tt:\implies Time(t) = 1 \: year \\ \\ \tt:\implies Rate\%(r) = 7\% \\ \\ \red{\underline \bold{To \:Find :}} \\ \tt :\implies Amount = ? \\ \\ \tt :\implies Compound \: Interest =?\end{gathered}

Given:

:⟹Principal(p)=20000rupees

:⟹Time(t)=1year

:⟹Rate%(r)=7%

ToFind:

:⟹Amount=?

:⟹CompoundInterest=?

• According to given question :

\begin{gathered}\bold{As \: we \: know \: that} \\ \tt: \implies A= p(1 + \frac{ \frac{r}{2} }{100})^{2t} \\ \\ \tt: \implies A =20000 \times (1 + \frac{7}{2 \times 100} )^{2} \\ \\ \tt: \implies A=20000 \times (1 + 0.035)^{2} \\ \\ \tt: \implies A =20000 \times 1.035 ^{2} \\ \\ \tt: \implies A =20000 \times 1.071225 \\ \\ \green{\tt: \implies A=21424.5 \: rupees} \\ \\ \bold{For \: compound \: interest} \\ \tt: \implies C.I = A - p \\ \\ \tt: \implies C.I =21424.5 - 20000 \\ \\ \green{\tt: \implies C.I =1424.5 \: rupees}\end{gathered}

Asweknowthat

:⟹A=p(1+

100

2

r

)

2t

:⟹A=20000×(1+

2×100

7

)

2

:⟹A=20000×(1+0.035)

2

:⟹A=20000×1.035

2

:⟹A=20000×1.071225

:⟹A=21424.5rupees

Forcompoundinterest

:⟹C.I=A−p

:⟹C.I=21424.5−20000

:⟹C.I=1424.5rupees