Question

Find 97 cube using algebraic identities

Answer 1

Answer:

97=90+7

therefore, (a+b)^3=a^3+b^3+ 3a^2b +3ab^2

now (90+7)^3=90^3+7^3+3*(90)^2*7+3*90*(7)^2

=912673

Answer 2

Answer:

See this.

Step-by-step explanation:

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