find 9th A.P when 4th A.P is 5 and 8th A.P is 15.
Answers
Answer:
the 9th term of the AP is 35/2
Step-by-step explanation:
a = -5/2
d = 5/2
Answer:
Step-by-step explanation:
- The 4th term of the A.P = 5
- The 8th term of the A.P = 15
- The 9th term of the A.P
⇝ Let us assume the first term of the A.P as a₁ and the common difference as d.
⇝ We know the nth term of an A.P is given by,
where a₁ is the first term and d is the common difference
⇝ Hence fourth term of the A.P is given by,
a₄ = a₁ + 3d
⇝ But by given the fourth term is 5.
a₁ + 3d = 5-----(1)
⇝ Also eight term of the A.P is given by,
a₈ = a₁ + 7d
⇝ By given eighth term of the A.P is 8.
a₁ + 7d = 15-----(2)
⇝ Solving equation 1 and 2 by elimination method,
a₁ + 7d = 15
a₁ + 3d = 5
7d = 10
d = 10/7
⇝ Hence the common difference of the A.P is 10/7.
⇝ Now substitute the value of d in equation 1,
a₁ + 3 × 10/7 = 5
a₁ = 5 - 30/7
a₁ = (35 - 30)/7
a₁ = 5/7
⇝ Hence first term of the A.P is 5/7.
⇝ Now finding the ninth term.
⇝ The ninth term of the A.P is given by,
a₉ = a₁ + 8d
a₉ = 5/7 + 8 × 10/7
a₉ = (5 + 80)/7
a₉ = 85/7
a₉ = 85/7
⇝ Hence the ninth term of the A.P is 85/7.