Math, asked by keshav18587, 1 year ago

find a^2+1/a^2 when a=3+2√2

Answers

Answered by MOSFET01
1
☺️✍️You get answer ..

1/a=1/(3+2√2)

rationalising denominator & numerator (3-2√2)

1/a= (3-2√2)/(3²-(2√2)²)

1/a= (3-2√2)/(9-(4×2))

1/a= (3-2√2)/(9-8)

1/a= (3-2√2)/1

1/a= (3-2√2)

now put the value of 1/a

remember
(a+b)²= a²+b²+2ab
:-(a+b)²-2ab=a²+b²+2ab-2ab
=>a²+b²

a²+1/a²=(a+1/a)²-2

=> (3+2√2+3-2√2)²-2

=> (6)²-2

==>(36)-2

==>34 answer

I hope it's help you..

keshav18587: while putting value -2 kaha se aaya
MOSFET01: (a+1/a)²= a²+1/a²+2(a)×(1/a)==> a²+1/a²+2(1)
MOSFET01: a²+1/a²+2-2=a²+1/a²
keshav18587: when we are putting (a+1/a)^3
keshav18587: what is the result
MOSFET01: (a+b)³ apply this
MOSFET01: (a+b)³=a³+3a²b+3ab²+b³
Answered by Ajay1291
1
hey mate here is your answer

=> a²+1/a²

=> a²+1=a²

=> (3+2√2)²+1=(3+2√2)²

=> 9+6√2+2+1=9+6√2+2*x

=> 9+2+1+6√2=9+2+6√2*x

=> 12+6√2= 11+6√2*x

=> 12+8.4852=11+8.4852*x

=> 20.4852=19.4852*x

=> 20.4852/19.4852=x


=> 1.051321002607106

is your answer

keshav18587: wrong
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