Math, asked by Achukphattadiiii, 1 year ago

Find a^2+ a + 1 = 0 , find the value of a^ 9

Answers

Answered by nayanu
0
a2+a+1=0
a2+a+a+1=0
a(a+1)+(a+1)=0
(a+1)(a+1)=0
a+1=0;a+1=0
a=-1;a=-1
value of (-1)^9 = -1
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