Question

find a^2+b^2 then a+b=8 and ab=12
please answer fast and correct please ​

Answer 1

Answer:

48

Step-by-step explanation:

a^2 + b^2 + 2ab=(a+b)^2

a^2+b^2+ 2*8=(8)^2

a^2+b^2+16=64

a^2+b^2=48

Answer 2

Step-by-step explanation:

Given

$(a + b) = 8 \: \: \: \: and \: \: \: \: ab = 12 \\ \\ (a + b) {}^{2} = 8 {}^{2} \\ \\ {a}^{2} + {b}^{2} + 2ab = 64 \\ \\ {a}^{2} + {b}^{2} + 2 \times 12 = 64 \\ \\ {a}^{2} + {b}^{2} + 24 = 64 \\ \\ {a}^{2} + {b}^{2} = 64 - 24 \\ \\ {a}^{2} + {b}^{2} = 40$