Question

Find a 2-digit smallest number which when divided by 1 , 2 and 3 leaves no remainder.

Answer 1

Answer:

12

Step-by-step explanation:

when 12 is divided with 2 then 2× 6 leaves remainder 0

when 12 is divided with 3 then 3×4 leaves remainder 0

Answer 2

Concept

The least common multiple or LCM is the number that is perfectly divisible by all the given numbers.

Given

a 2-digit number when divided by 1 , 2 and 3 leaves no remainder.

Find

we need to find the smallest such number

Solution

We have 1, 2 and 3

The smallest number which will divide 1, 2 and 3 perfectly, leaving no remainder will be the LCM of these numbers.

The LCM of 1, 2 and 3 will be 6

To check we can see that

6/1 = 1

6/2 = 3

and 6/3 = 2

Thus, all the numbers completely divide 6.

But 6 is not a two digit number, so try and see what happens when we multiply 6 by 2

6 * 2 = 12

12 is a 2 digit number and also the next number after 6 that will be divisible by 1,2 and 3.

Thus, the smallest 2-digit number which when divided by 1 , 2 and 3 leaves no remainder is 12.

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