Find a^4+b^4+c^4
Solve it.
Answers
Answered by
2
Answer:
a^4+b^4+c^4
= (a²+b²+c²)²-2(a²b²+b²c²+c²a²)
= {(a+b+c)²-2(ab+bc+ca)}²
-2(a²b²+b²c²+c²a²)
= (a+b+c)^4+4(ab+bc+ca)²
-4(ab+bc+ca)(a+b+c)²
-2(a²b²+b²c²+c²a²)
Answered by
2
Answer:
a⁴+b⁴+c⁴+4a²b²+4b²c²+4c²a²
step by step explanation:
•(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
a⁴+b⁴+c⁴= [(a+b+c)²]²
[(a²+b²+c²+2ab+2bc+2ca)]²
(a²)²+(b²)²+(c²)²+(2ab)²+(2bc)²+(2ca)²
a⁴+b⁴+c⁴+4a²b²+4b²c²+4c²a²
Similar questions