Find a 4-digit odd number using each of the digits 1,2,4,5 only once such that when the first and the last digits are interchanged ,it is divisible by 4.
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Answered by
23
4152 ÷ 4 = 1038 can be the number divisible by 4 on interchange as 2154 ÷4 = 538
Answered by
13
Hi.....dear..
...
.here is your answer....
..the problem can be solved logically...there are only two odd numbers 1 and 5 ...
when we place 5 at last place and 4 at fourth place we got number can be 4215 or 4125..
now try to interchange both first' and last mummers.....we get 5214 or 5124.......we observe that 5124is divisible by 4.....so number will be 4125.....
similarly you can find that 4521 is also an answer
4521 and 4125.......
it an odd number which contains each of the digits 1, 2, 4 and 5 only once. that when the first and the last digits are interchanged, it is divisible by 4.
.....!!!!!!!.
Hope it helped you!!!.
Regards Brainly Star Community
#shubhendu
...
.here is your answer....
..the problem can be solved logically...there are only two odd numbers 1 and 5 ...
when we place 5 at last place and 4 at fourth place we got number can be 4215 or 4125..
now try to interchange both first' and last mummers.....we get 5214 or 5124.......we observe that 5124is divisible by 4.....so number will be 4125.....
similarly you can find that 4521 is also an answer
4521 and 4125.......
it an odd number which contains each of the digits 1, 2, 4 and 5 only once. that when the first and the last digits are interchanged, it is divisible by 4.
.....!!!!!!!.
Hope it helped you!!!.
Regards Brainly Star Community
#shubhendu
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