Question

find a amd b such that 27,a,b,-6 are in AP​

Answer 1

Answer:

a=14 & b=21

Step-by-step explanation: we have, 27,a,b,-6 in AP

now, we can write a = 27+b/2 -----------------(1)

 & b=a-6/2 --------------------------------------------(2)

now, on putting the value of a in (2) equation we get,

b=27+b-6/2

2b=21+b

2b-b=21

b=21

now, on putting the value of b in (2) equation we get,

a=27+21/2

a=28/2

a=14

Answer 2

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Here is Your Answer...!!

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Step by step solution:

$For \ three \ terms \ of \ A.P. \ we \ know \ that\\\\2q=p+r\\\\2a=27+b \ ...(i)\\\\2b=-6+a \ (multiply \ by \ 2)\\\\4b+12=2a \ ...(ii)\\\\From \ (i) \ and \ (ii) \ we \ have\\\\27+b=4b+12\\\\3b=15\\\\b=5\\\\Now \ putting \ b=5 \ in \ (i)\\\\2a=27+b\\\\2a=27+5\\\\2a=32\\\\a=16\\\\So \ we \ get \ a=16 \ and \ b=5$

Hope it is clear to you.