Question

find a & b 2+3√3 ÷ √3-2= a+b√3​

Answer 1

Answer :

a= -13, b= -8

Brief Explanation :

=> 2 + $\sqrt[3]{3}$ / $\sqrt{3}$ - 2 = a + b$\sqrt{3}$

= 2 + $\sqrt[3]{3}$ / $\sqrt{3}$ - 2 *  $\sqrt{3}$ + 2 / $\sqrt{3}$ + 2

= (2 + $\sqrt[3]{3}$) ($\sqrt{3}$ + 2) / 3 - 4

= 2$\sqrt{3}$ + 4 + 9 + 6$\sqrt{3}$ / -1

= 13 + 8$\sqrt{3}$ / -1

= -13 -18$\sqrt{3}$

Therefore, a = -13 and b = -8