find a and b : √2 -1 / √2+1 =a+b√2
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Answer:
LHS=
√2-1/√2+1 *√2-1/√2-1
=(√2-1)^2/(√2)^2-1
=(2+1-2√2)/2-1
=3-2√2/1
=3-2√2
hence,
a=3. and b=-2.
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