find a and b if 2 root 5+ root 3 divided by 2 root 5 - root 3 + 2 root 5- root 3 divided by 2 root 5 + root 3 is equal to a+ root 15b
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Answered by
8
Answer:
Hey Mate...
Step-by-step explanation:
root5 + root 3 / root5 - root3 => A + B root15
rationalize , ..... (rt5 + rt3 )^2 / (rt5)^2 - (rt3)^2
=> 5 + 2rt15 + 3 / 5 - 3
8 + 2rt15 / 2 => 2( 4 + rt15 ) / 2
2 gets cancel by division so,
4 + rt15 = A + B rt15
therefore, A = 4 and B = 1
Answered by
8
Answer:
Step-by-step explanation:
Hey ,
Let take up the values,
root5 + root 3 / root5 - root3 => A + B root15
(rt5 + rt3 )^2 / (rt5)^2 - (rt3)^2[By rationalization method].
=> 5 + 2rt15 + 3 / 5 - 3
8 + 2rt15 / 2 => 2( 4 + rt15 ) / 2
2 gets cancel by division so,
4 + rt15 = A + B rt15(roots are cancelled on both sides).
A = 4 and B = 1
So, therefore we can conclude that A=4 and B=1.
Step-by-step explanation:
Hey ,
Let take up the values,
root5 + root 3 / root5 - root3 => A + B root15
(rt5 + rt3 )^2 / (rt5)^2 - (rt3)^2[By rationalization method].
=> 5 + 2rt15 + 3 / 5 - 3
8 + 2rt15 / 2 => 2( 4 + rt15 ) / 2
2 gets cancel by division so,
4 + rt15 = A + B rt15(roots are cancelled on both sides).
A = 4 and B = 1
So, therefore we can conclude that A=4 and B=1.
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