Question

Find a and b , if 2a sq. + 2b sq. + 4ab = 98 and a - b = 3

Answer 1

$\: \: \: \: \: 2(2 {a}^{2} + 2 {b}^{2} + 4ab) = 2 \times 98 \\ =>( {2}a + {2}b)^{2} = 196 \\ = > (2a + 2b) = 14 \: and \: - 14 \\ = >a + b = 7 \: and \: - 7$
And given,
a-b = 3
Solving both the equations by
taking +7 and - 7.


a = 5 and -5.
b = 2 and -2.




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