find a and b if 3√2+2√3/5√2-4√3=a-b√6
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Hiiii friend,
3✓2+2✓3/5✓2-4✓3
Rationalizing the denominator 5✓2-4✓3
=> 3✓2 + 2✓3/5✓2 -4✓3 × 5✓2+4✓3/5✓2+4✓3
=> (3✓2+2✓3)(5✓2+4✓3)/(5✓2-4✓3)(5✓2+4✓3)
=> 3✓2(5✓2+4✓3)+2✓3(5✓2+4✓3)/(5✓2)² - (4✓3)²
=> 30 + 12✓6 + 10✓6 + 24/50 - 48
=> 54+22✓6/2
=> 2(27+11✓6)/3
=> 27+11✓6
Now,
LHS = RHS
27+11✓6 = A+B✓6
Clearly,
A = 27 And B = 11
HOPE IT WILL HELP YOU..... :-)
3✓2+2✓3/5✓2-4✓3
Rationalizing the denominator 5✓2-4✓3
=> 3✓2 + 2✓3/5✓2 -4✓3 × 5✓2+4✓3/5✓2+4✓3
=> (3✓2+2✓3)(5✓2+4✓3)/(5✓2-4✓3)(5✓2+4✓3)
=> 3✓2(5✓2+4✓3)+2✓3(5✓2+4✓3)/(5✓2)² - (4✓3)²
=> 30 + 12✓6 + 10✓6 + 24/50 - 48
=> 54+22✓6/2
=> 2(27+11✓6)/3
=> 27+11✓6
Now,
LHS = RHS
27+11✓6 = A+B✓6
Clearly,
A = 27 And B = 11
HOPE IT WILL HELP YOU..... :-)
abarajith8769:
thanks
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