find a and b if 3/√3-√2=a√3-b√2
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a=3 and b=-3
Firstly rationalise 3/3^1/2 - 2^1/2 so that would be 3(3^1/2 +2^1/2)
therefore , 3×3^1/2 -(-3×2^1/2) = a×3^1/2 - b×2^1/2
so a =3 and b=-3
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