Find a and b if 3+√6/√3+√2=a+b√3
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Answer:
a=0
b=1
Step-by-step explanation:
taking L.H.S,
3+√6/√3+√2 = 3+√6 [ √3-√2 ] / [√3-√2 ]
= 3√3 - 3√2 + 3√2 -2√3
= 0 + 1√3
on comparing it with R.H.S,
We get,
a=0,b=1
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