Math, asked by topirina976, 7 months ago

Find a and b if 3+√6/√3+√2=a+b√3

Answers

Answered by Anonymous
2

Answer:

a=0

b=1

Step-by-step explanation:

taking L.H.S,

3+√6/√3+√2 = 3+√6 [ √3-√2 ] / [√3-√2 ]

= 3√3 - 3√2 + 3√2 -2√3

= 0 + 1√3

on comparing it with R.H.S,

We get,

a=0,b=1

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