find a and b if 3+sqare root 6 by sqare root +3 sqare root 2
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Step-by-step explanation:
(3+√6) / (√3+√2)
On rationalising the denominator,
(3+√6)×(√3-√2) / (✓3+√2)×(√3-√2)
= (3√3 - 3√2 + 3√2 - 2√3) / (√3)² - (√2)²
= √3
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